Refactor: to Portuguese for English.

Author: CodeMayPy

ex059.py

@@ -1,4 +1,4 @@
-#Create a program that reads two values and displays a menu on the screen:
+#59-Create a program that reads two values and displays a menu on the screen:
 #[ 1 ] add
 #[ 2 ] multiply
 #[ 3 ] bigger

ex060.py

@@ -1,4 +1,4 @@
-# Write a program that reads any number and displays its factorial.
+#60- Write a program that reads any number and displays its factorial.
 # just in four lines
 '''from math import factorial
 number = int(input('Enter a number:'))

ex061.py

@@ -1,4 +1,4 @@
-#  Redo CHALLENGE 51, reading the first term and the reason of an AP, showing the first 10 terms of the progression
+#61-  Redo CHALLENGE 51, reading the first term and the reason of an AP, showing the first 10 terms of the progression
 #  using the while structure.
 print("Arithmetic progression generator")
 print("-=-" * 20)

ex062.py

@@ -1,4 +1,4 @@
-# Improve challenge 61 by asking the user if he wants to show some more terms. The program will exit when he says he
+#62- Improve challenge 61 by asking the user if he wants to show some more terms. The program will exit when he says he
 # wants to show 0 terms.
 print("Arithmetic progression generator")
 print("-=-" * 20)

ex063.py

@@ -1,4 +1,4 @@
-#Write a program that reads any integer number N and displays on the screen the first N elements of a
+#63-Write a program that reads any integer number N and displays on the screen the first N elements of a
 # Fibonacci Sequence.
 terms = int(input("How many terms do you want to show?"))
 first_term = 0

ex064.py

@@ -1,4 +1,4 @@
-#Create a program that reads several integers from the keyboard. The program will only stop when the user enters the
+#64-Create a program that reads several integers from the keyboard. The program will only stop when the user enters the
 # value 999, which is the stopping condition. At the end, show how many numbers were entered and what the sum of them
 # was (disregarding the flag).
 number = counter = amount = 0