From 5fe8ef3cb27141f041a45e8697958e562e5882e3 Mon Sep 17 00:00:00 2001 From: Nathylyn <88753323+Nathylyn@users.noreply.github.com> Date: Sat, 28 Aug 2021 14:41:39 -0400 Subject: [PATCH 1/2] Delete main.ipynb --- your-code/main.ipynb | 336 ------------------------------------------- 1 file changed, 336 deletions(-) delete mode 100755 your-code/main.ipynb diff --git a/your-code/main.ipynb b/your-code/main.ipynb deleted file mode 100755 index 66a9984..0000000 --- a/your-code/main.ipynb +++ /dev/null @@ -1,336 +0,0 @@ -{ - "cells": [ - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "# Before your start:\n", - "- Read the README.md file\n", - "- Comment as much as you can and use the resources in the README.md file\n", - "- Happy learning!" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "# Challenge 1 - Passing a Lambda Expression to a Function\n", - "\n", - "In the next excercise you will create a function that returns a lambda expression. Create a function called `modify_list`. The function takes two arguments, a list and a lambda expression. The function iterates through the list and applies the lambda expression to every element in the list." - ] - }, - { - "cell_type": "raw", - "metadata": {}, - "source": [ - "Follow the steps as stated below:\n", - " 1. Define a list of any 10 numbers\n", - " 2. Define a simple lambda expression for eg that updates a number by 2\n", - " 3. Define an empty list\n", - " 4. Define the function -> use the lambda function to append the empty list\n", - " 5. Call the function with list and lambda expression\n", - " 6. print the updated list " - ] - }, - { - "cell_type": "code", - "execution_count": null, - "metadata": {}, - "outputs": [], - "source": [ - "l = [######]\n", - "f = lambda x: #define the lambda expression\n", - "b = []\n", - "def modify_list(lst, fudduLambda):\n", - " for x in ####:\n", - " b.append(#####(x))\n", - "#Call modify_list(##,##)\n", - "#print b" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "#### Now we will define a lambda expression that will transform the elements of the list. \n", - "\n", - "In the cell below, create a lambda expression that converts Celsius to Kelvin. Recall that 0°C + 273.15 = 273.15K" - ] - }, - { - "cell_type": "code", - "execution_count": 3, - "metadata": {}, - "outputs": [], - "source": [ - "# Your code here:\n", - "\n" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "Finally, convert the list of temperatures below from Celsius to Kelvin." - ] - }, - { - "cell_type": "code", - "execution_count": 4, - "metadata": {}, - "outputs": [], - "source": [ - "temps = [12, 23, 38, -55, 24]\n", - "\n", - "# Your code here:" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "#### In this part, we will define a function that returns a lambda expression\n", - "\n", - "In the cell below, write a lambda expression that takes two numbers and returns 1 if one is divisible by the other and zero otherwise. Call the lambda expression `mod`." - ] - }, - { - "cell_type": "code", - "execution_count": 5, - "metadata": {}, - "outputs": [], - "source": [ - "# Your code here:\n" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "#### Now create a function that returns mod. The function only takes one argument - the first number in the `mod` lambda function. \n", - "\n", - "Note: the lambda function above took two arguments, the lambda function in the return statement only takes one argument but also uses the argument passed to the function." - ] - }, - { - "cell_type": "code", - "execution_count": 6, - "metadata": {}, - "outputs": [], - "source": [ - "def divisor(b):\n", - " \"\"\"\n", - " input: a number\n", - " output: a function that returns 1 if the number is divisible by another number (to be passed later) and zero otherwise\n", - " \"\"\"\n", - " \n", - " # Your code here:" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "Finally, pass the number 5 to `divisor`. Now the function will check whether a number is divisble by 5. Assign this function to `divisible5`" - ] - }, - { - "cell_type": "code", - "execution_count": 7, - "metadata": {}, - "outputs": [], - "source": [ - "# Your code here:\n" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "Test your function with the following test cases:" - ] - }, - { - "cell_type": "code", - "execution_count": null, - "metadata": {}, - "outputs": [], - "source": [ - "divisible5(10)" - ] - }, - { - "cell_type": "code", - "execution_count": null, - "metadata": {}, - "outputs": [], - "source": [ - "divisible5(8)" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "# Challenge 2 - Using Lambda Expressions in List Comprehensions\n", - "\n", - "In the following challenge, we will combine two lists using a lambda expression in a list comprehension. \n", - "\n", - "To do this, we will need to introduce the `zip` function. The `zip` function returns an iterator of tuples.\n", - "\n", - "The way zip function works with list has been shown below:" - ] - }, - { - "cell_type": "code", - "execution_count": 1, - "metadata": {}, - "outputs": [ - { - "data": { - "text/plain": [ - "[('Green', 'eggs'),\n", - " ('cheese', 'cheese'),\n", - " ('English', 'cucumber'),\n", - " ('tomato', 'tomato')]" - ] - }, - "execution_count": 1, - "metadata": {}, - "output_type": "execute_result" - } - ], - "source": [ - "list1 = ['Green', 'cheese', 'English', 'tomato']\n", - "list2 = ['eggs', 'cheese', 'cucumber', 'tomato']\n", - "zipped = zip(list1,list2)\n", - "list(zipped)" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "In this exercise we will try to compare the elements on the same index in the two lists. \n", - "We want to zip the two lists and then use a lambda expression to compare if:\n", - "list1 element > list2 element " - ] - }, - { - "cell_type": "code", - "execution_count": 3, - "metadata": {}, - "outputs": [], - "source": [ - "list1 = [1,2,3,4]\n", - "list2 = [2,3,4,5]\n", - "## Zip the lists together \n", - "## Print the zipped list " - ] - }, - { - "cell_type": "raw", - "metadata": {}, - "source": [ - "Complete the parts of the code marked as \"###\"" - ] - }, - { - "cell_type": "code", - "execution_count": 4, - "metadata": {}, - "outputs": [ - { - "data": { - "text/plain": [ - "'\\n\\ncompare = lambda ###: print(\"True\") if ### else print(\"False\")\\nfor ### in zip(list1,list2):\\n compare(###)\\n \\n'" - ] - }, - "execution_count": 4, - "metadata": {}, - "output_type": "execute_result" - } - ], - "source": [ - "'''\n", - "\n", - "compare = lambda ###: print(\"True\") if ### else print(\"False\")\n", - "for ### in zip(list1,list2):\n", - " compare(###)\n", - " \n", - "''' " - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "# Challenge 3 - Using Lambda Expressions as Arguments\n", - "\n", - "#### In this challenge, we will zip together two lists and sort by the resulting tuple.\n", - "\n", - "In the cell below, take the two lists provided, zip them together and sort by the first letter of the second element of each tuple. Do this using a lambda function." - ] - }, - { - "cell_type": "code", - "execution_count": 12, - "metadata": {}, - "outputs": [], - "source": [ - "list1 = ['Engineering', 'Computer Science', 'Political Science', 'Mathematics']\n", - "list2 = ['Lab', 'Homework', 'Essay', 'Module']\n", - "\n", - "# Your code here:\n" - ] - }, - { - "cell_type": "markdown", - "metadata": {}, - "source": [ - "# Bonus Challenge - Sort a Dictionary by Values\n", - "\n", - "Given the dictionary below, sort it by values rather than by keys. Use a lambda function to specify the values as a sorting key." - ] - }, - { - "cell_type": "code", - "execution_count": 13, - "metadata": {}, - "outputs": [], - "source": [ - "d = {'Honda': 1997, 'Toyota': 1995, 'Audi': 2001, 'BMW': 2005}\n", - "\n", - "# Your code here:" - ] - }, - { - "cell_type": "code", - "execution_count": null, - "metadata": {}, - "outputs": [], - "source": [] - } - ], - "metadata": { - "kernelspec": { - "display_name": "Python 3", - "language": "python", - "name": "python3" - }, - "language_info": { - "codemirror_mode": { - "name": "ipython", - "version": 3 - }, - "file_extension": ".py", - "mimetype": "text/x-python", - "name": "python", - "nbconvert_exporter": "python", - "pygments_lexer": "ipython3", - "version": "3.7.3" - } - }, - "nbformat": 4, - "nbformat_minor": 2 -} From 81d9182c627c7ead6602b723dc5bd4f652690d59 Mon Sep 17 00:00:00 2001 From: Nathylyn <88753323+Nathylyn@users.noreply.github.com> Date: Sat, 28 Aug 2021 14:42:49 -0400 Subject: [PATCH 2/2] Add files via upload --- your-code/main.ipynb | 449 +++++++++++++++++++++++++++++++++++++++++++ 1 file changed, 449 insertions(+) create mode 100644 your-code/main.ipynb diff --git a/your-code/main.ipynb b/your-code/main.ipynb new file mode 100644 index 0000000..1cf495e --- /dev/null +++ b/your-code/main.ipynb @@ -0,0 +1,449 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Before your start:\n", + "- Read the README.md file\n", + "- Comment as much as you can and use the resources in the README.md file\n", + "- Happy learning!" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Challenge 1 - Passing a Lambda Expression to a Function\n", + "\n", + "In the next excercise you will create a function that returns a lambda expression. Create a function called `modify_list`. The function takes two arguments, a list and a lambda expression. The function iterates through the list and applies the lambda expression to every element in the list." + ] + }, + { + "cell_type": "raw", + "metadata": {}, + "source": [ + "Follow the steps as stated below:\n", + " 1. Define a list of any 10 numbers\n", + " 2. Define a simple lambda expression for eg that updates a number by 2\n", + " 3. Define an empty list\n", + " 4. Define the function -> use the lambda function to append the empty list\n", + " 5. Call the function with list and lambda expression\n", + " 6. print the updated list " + ] + }, + { + "cell_type": "code", + "execution_count": 3, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "[2, 4, 6, 8, 10, 12, 14, 16, 18, 20]\n" + ] + } + ], + "source": [ + "l = [i+1 for i in range(10)]\n", + "f = lambda x: 2*x\n", + "b = []\n", + "def modify_list(lst, fudduLambda):\n", + " for x in lst:\n", + " b.append(fudduLambda(x))\n", + "modify_list(l,f)\n", + "print(b)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Now we will define a lambda expression that will transform the elements of the list. \n", + "\n", + "In the cell below, create a lambda expression that converts Celsius to Kelvin. Recall that 0°C + 273.15 = 273.15K" + ] + }, + { + "cell_type": "code", + "execution_count": 5, + "metadata": {}, + "outputs": [ + { + "data": { + "text/plain": [ + "288.15" + ] + }, + "execution_count": 5, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "# Your code here:\n", + "k=lambda x: x+273.15\n", + "k(15)\n" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "Finally, convert the list of temperatures below from Celsius to Kelvin." + ] + }, + { + "cell_type": "code", + "execution_count": 9, + "metadata": {}, + "outputs": [ + { + "data": { + "text/plain": [ + "[285.15, 296.15, 311.15, 218.14999999999998, 297.15]" + ] + }, + "execution_count": 9, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "temps = [12, 23, 38, -55, 24]\n", + "\n", + "# Your code here:\n", + "def modify(lst, l):\n", + " return [l(e) for e in lst]\n", + "\n", + "modify(temps, k)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### In this part, we will define a function that returns a lambda expression\n", + "\n", + "In the cell below, write a lambda expression that takes two numbers and returns 1 if one is divisible by the other and zero otherwise. Call the lambda expression `mod`." + ] + }, + { + "cell_type": "code", + "execution_count": 10, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "0\n", + "1\n" + ] + } + ], + "source": [ + "# Your code here:\n", + "mod=lambda i,j: 1 if i%j==0 or j%i==0 else 0\n", + "print (mod(5,7))\n", + "print (mod(2,4))" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Now create a function that returns mod. The function only takes one argument - the first number in the `mod` lambda function. \n", + "\n", + "Note: the lambda function above took two arguments, the lambda function in the return statement only takes one argument but also uses the argument passed to the function." + ] + }, + { + "cell_type": "code", + "execution_count": 11, + "metadata": {}, + "outputs": [], + "source": [ + "def divisor(b):\n", + " \"\"\"\n", + " input: a number\n", + " output: a function that returns 1 if the number is divisible by another number (to be passed later) and zero otherwise\n", + " \"\"\"\n", + " \n", + " # Your code here:\n", + " return lambda i,b: 1 if b%i==0 else 0" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "Finally, pass the number 5 to `divisor`. Now the function will check whether a number is divisble by 5. Assign this function to `divisible5`" + ] + }, + { + "cell_type": "code", + "execution_count": 12, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here:\n", + "def divisible5(b):\n", + " mod=lambda i,b: 1 if b%i==0 else 0\n", + " return mod(5,b)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "Test your function with the following test cases:" + ] + }, + { + "cell_type": "code", + "execution_count": 13, + "metadata": {}, + "outputs": [ + { + "data": { + "text/plain": [ + "1" + ] + }, + "execution_count": 13, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "divisible5(10)" + ] + }, + { + "cell_type": "code", + "execution_count": 14, + "metadata": {}, + "outputs": [ + { + "data": { + "text/plain": [ + "0" + ] + }, + "execution_count": 14, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "divisible5(8)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Challenge 2 - Using Lambda Expressions in List Comprehensions\n", + "\n", + "In the following challenge, we will combine two lists using a lambda expression in a list comprehension. \n", + "\n", + "To do this, we will need to introduce the `zip` function. The `zip` function returns an iterator of tuples.\n", + "\n", + "The way zip function works with list has been shown below:" + ] + }, + { + "cell_type": "code", + "execution_count": 15, + "metadata": {}, + "outputs": [ + { + "data": { + "text/plain": [ + "[('Green', 'eggs'),\n", + " ('cheese', 'cheese'),\n", + " ('English', 'cucumber'),\n", + " ('tomato', 'tomato')]" + ] + }, + "execution_count": 15, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "list1 = ['Green', 'cheese', 'English', 'tomato']\n", + "list2 = ['eggs', 'cheese', 'cucumber', 'tomato']\n", + "zipped = zip(list1,list2)\n", + "list(zipped)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "In this exercise we will try to compare the elements on the same index in the two lists. \n", + "We want to zip the two lists and then use a lambda expression to compare if:\n", + "list1 element > list2 element " + ] + }, + { + "cell_type": "code", + "execution_count": 16, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "[(1, 2), (2, 3), (3, 4), (4, 5)]\n" + ] + } + ], + "source": [ + "list1 = [1,2,3,4]\n", + "list2 = [2,3,4,5]\n", + "## Zip the lists together \n", + "## Print the zipped list \n", + "zipped=list(zip(list1, list2))\n", + "print (zipped)" + ] + }, + { + "cell_type": "raw", + "metadata": {}, + "source": [ + "Complete the parts of the code marked as \"###\"" + ] + }, + { + "cell_type": "code", + "execution_count": 18, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "False\n", + "False\n", + "False\n", + "False\n" + ] + } + ], + "source": [ + "'''\n", + "\n", + "compare = lambda ###: print(\"True\") if ### else print(\"False\")\n", + "for ### in zip(list1,list2):\n", + " compare(###)\n", + " \n", + "''' \n", + "compare = lambda i: print(\"True\") if i[0]>i[1] else print(\"False\")\n", + "for e in zip(list1,list2):\n", + " compare(e)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Challenge 3 - Using Lambda Expressions as Arguments\n", + "\n", + "#### In this challenge, we will zip together two lists and sort by the resulting tuple.\n", + "\n", + "In the cell below, take the two lists provided, zip them together and sort by the first letter of the second element of each tuple. Do this using a lambda function." + ] + }, + { + "cell_type": "code", + "execution_count": 20, + "metadata": {}, + "outputs": [ + { + "data": { + "text/plain": [ + "[('Political Science', 'Essay'),\n", + " ('Computer Science', 'Homework'),\n", + " ('Engineering', 'Lab'),\n", + " ('Mathematics', 'Module')]" + ] + }, + "execution_count": 20, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "list1 = ['Engineering', 'Computer Science', 'Political Science', 'Mathematics']\n", + "list2 = ['Lab', 'Homework', 'Essay', 'Module']\n", + "\n", + "# Your code here:\n", + "zipped=list(zip(list1,list2))\n", + "sorted(zipped, key=lambda i: i[1])" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Bonus Challenge - Sort a Dictionary by Values\n", + "\n", + "Given the dictionary below, sort it by values rather than by keys. Use a lambda function to specify the values as a sorting key." + ] + }, + { + "cell_type": "code", + "execution_count": 21, + "metadata": {}, + "outputs": [ + { + "data": { + "text/plain": [ + "[('Toyota', 1995), ('Honda', 1997), ('Audi', 2001), ('BMW', 2005)]" + ] + }, + "execution_count": 21, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "d = {'Honda': 1997, 'Toyota': 1995, 'Audi': 2001, 'BMW': 2005}\n", + "\n", + "sorted(d.items(), key=lambda i: i[1])" + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 3", + "language": "python", + "name": "python3" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 3 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython3", + "version": "3.8.8" + } + }, + "nbformat": 4, + "nbformat_minor": 2 +}