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Trees.js
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263 lines (222 loc) · 7.21 KB
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//Trees are different from a linked list by having more than one node extending from the root
//Linked lists are also a type of tree, but linear
//Nodes inside of a tree can only point to the child nodes
//A binary tree is a tree with each node that can only have 0,1 or 2 child nodes and every child node is supposed to have only one parent
//Right Node is greater than left node
//BST have a time complexity of O (log n)
//No O(1) opreations
//Unbalanced trees turn into long lists
class Node {
constructor(value) {
this.value = value;
this.left = null;
this.right = null;
}
}
class BinaryTree {
constructor() {
this.root = null;
}
insert (value) {
const newNode = new Node(value);
if (this.root == null) {this.root = newNode;
} else {
let currentNode = this.root;
while (true) {
if (value < currentNode.value) {
if (!currentNode.left) {
currentNode.left = newNode;
return this;
}
currentNode = currentNode.left;
} else {
if (value > currentNode.value) {
if(!currentNode.right) {
currentNode.right = newNode;
return this;
}
currentNode = currentNode.right;
}
}
}
}
}
remove (value) {
if (!this.root) {
return false;
}
let currentNode = this.root;
let parentNode = null;
while(currentNode) {
if (value < currentNode.value) {
parentNode = currentNode;
currentNode = currentNode.left;
} else if (value > currentNode.value) {
parentNode = currentNode;
currentNode = currentNode.right;
} else if (currentNode.value === value) {
//Option 1: No right child:
if (currentNode.right === null) {
if (parentNode === null) {
this.root = currentNode.left;
} else {
//if parent > current value, make current left child a child of parent
if (currentNode.value < parentNode.value) {
parentNode.left = currentNode.left;
//if parent < current value, make left child a right child of parent
} else if (currentNode.value > parentNode.value) {
parentNode.right = currentNode.left;
}
}
//Option 2: Right child which doesn't have a left child
} else if (currentNode.right.left === null) {
currentNode.right.left = currentNode.left;
if(parentNode === null) {
this.root = currentNode.right;
} else {
//if parent > current, make right child of the left the parent
if (currentNode.value < parentNode.value) {
parentNode.left = currentNode.right;
//if parent < current, make right child a right child of the parent
} else if (currentNode.value > parentNode.value) {
parentNode.right = currentNode.right;
}
}
//Option 3: Right child that has a left child
} else {
//find the Right child's left most child
let leftmost = currentNode.right.left;
let leftmostParent = currentNode.right;
while (leftmost.left !== null) {
leftmostParent = leftmost;
leftmost = leftmost.left;
}
//Parent's left subtree is now leftmost's right subtree
leftmostParent.left = leftmost.right;
leftmost.left = currentNode.left;
leftmost.right = currentNode.right;
if(parentNode === null) {
this.root = leftmost;
} else {
if(currentNode.value < parentNode.value) {
parentNode.left = leftmost;
} else if(currentNode.value > parentNode.value) {
parentNode.right = leftmost;
}
}
}
return true;
}
}
}
lookUp(val) {
if (!this.root) return false;
else {
let currentNode = this.root;
while (currentNode) {
if (val > currentNode.value) {
currentNode = currentNode.right;
} else if (val < currentNode.value) {
currentNode = currentNode.left;
} else if (val == currentNode.value) {
return true;
}
}
}
return false;
}
BFS () {
let currentNode = this.root;
let list = [];
let queue = [];
queue.push(currentNode);
while (queue.length > 0) {
currentNode = queue.shift();
console.log(queue)
console.log(currentNode.value);
list.push(currentNode.value);
if (currentNode.left) {
queue.push(currentNode.left);
}
if (currentNode.right) {
queue.push(currentNode.right);
}
}
return list;
}
BFSRecursive(queue, list) {
if (queue.length == 0) {
return list;
}
let currentNode = queue.shift();
list.push(currentNode.value);
if (currentNode.left) {
queue.push(currentNode.left);
}
if (currentNode.right) {
queue.push(currentNode.right);
}
return this.BFSRecursive(queue, list);
}
DFSInOrder() {
return traverseInOrder(this.root, []);
}
DFSPostOrder() {
return traversePostOrder(this.root, []);
}
DFSPreOrder() {
return traversePreOrder(this.root, []);
}
}
function traversePreOrder(node, list){
list.push(node.value);
if(node.left) {
traversePreOrder(node.left, list);
}
if(node.right) {
traversePreOrder(node.right, list);
}
return list;
}
function traverseInOrder(node, list){
if(node.left) {
traverseInOrder(node.left, list);
}
list.push(node.value);
if(node.right) {
traverseInOrder(node.right, list);
}
return list;
}
function traversePostOrder(node, list){
if(node.left) {
traversePostOrder(node.left, list);
}
if(node.right) {
traversePostOrder(node.right, list);
}
list.push(node.value);
return list;
}
const tree = new BinaryTree();
tree.insert(9);
tree.insert(4);
tree.insert(20);
tree.insert(1);
tree.insert(6);
tree.insert(15);
tree.insert(170);
console.log(tree.DFSInOrder());
console.log(tree.DFSPreOrder());
console.log(tree.DFSPostOrder());
console.log(tree);
console.log(tree.lookUp(7));
//
// 9
// 4 20
// 1 6 15 270
//
//
//
//
//