token的时候create_one_batch方法中获取bow和eow的id的时候为什么互换了两个id的位置 #105
Description
bow_id, eow_id, oov_id, pad_id = [char2id.get(key, None) for key in ('', '', oov, pad)]
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bow_id, eow_id, oov_id, pad_id = [char2id.get(key, None) for key in ('', '', oov, pad)]