chore: add daily leetcode post 2679.矩阵中的和_translated

Author: longsizhuo

app/docs/CommunityShare/Leetcode/2679.矩阵中的和_translated.md

@@ -0,0 +1,79 @@
+---
+title: 2679.In the matrix and the harmony.md
+date: '2024.01.01 0:00'
+tags:
+  - - Python
+  - - answer
+  - - Array
+  - - matrix
+  - - Sort
+  - - simulation
+  - - heap（Priority queue）
+abbrlink: '5277100'
+---
+
+# topic：
+
+[2679.In the matrix and the harmony.md](https://leetcode.cn/problems/sum-in-a-matrix/)
+
+# Thought：
+**One -line**
+First of all, the meaning is to find the largest number of each sub -list，Thenpopgo out，Finally ask for peace。
+The effect of traversing again and again is too bad，So I thought of using itzip一次性Traversal多个子Array。
+于yes先对每个子ArraySort，Then usezipTraversal，Find the maximum。
+for example：
+`nums = [[7,2,1],[6,4,2],[6,5,3],[3,2,1]]`
+Sort后：
+`nums = [[1,2,7],[2,4,6],[3,5,6],[1,2,3]]`
+Then usezipTraversal得到：
+`[(1,2,3,1),(2,4,5,2),(7,6,6,3)]`
+Find the maximum：
+`[3,5,7]`
+Context：
+`15`
+# Code：
+
+```python
+class Solution:
+    def matrixSum(self, nums: List[List[int]]) -> int:
+        return sum(max(i) for i in \
+        zip(*(sorted(sublist) for sublist in nums)))
+```
+### *The role and the rolezip()explain
+```python 
+nums = [[1,2,7],[2,4,6],[3,5,6],[1,2,3]]
+
+for i in range(len(nums[1])):
+    for j in range(len(nums)):
+        print(nums[j][i])
+# ans = 123124527663
+num1 = [1,2,7]
+num2 = [2,4,6]
+num3 = [3,5,6]
+num4 = [1,2,3]
+```
+`zip()`The function corresponds to one -to -one elements in multiple lists，Then return onezipObject，Can uselist()Function convert to list。
+```python
+for i in zip(num1, num2, num3, num4):
+    print(i)
+#(1, 2, 3, 1)
+#(2, 4, 5, 2)
+#(7, 6, 6, 3)
+```
+`*nums`The role ispythonNot a pointer，InsteadnumsEach element in the parameter is passed into the function。I understand here as a list。
+```python
+
+# Enumerate
+print(*nums)
+# [1, 2, 7] [2, 4, 6] [3, 5, 6] [1, 2, 3]
+```
+`zip(*nums)`WillnumsEach element is passed in as a parameterzip()In the function，Then return onezipObject，Can uselist()Function convert to list。
+`zip(*nums)`Equivalent to`zip(num1, num2, num3, num4)`，innum1, num2, num3, num4yesnumsElement。
+```python
+for i in zip(*nums):
+    print(i)
+# Equivalent
+#(1, 2, 3, 1)
+#(2, 4, 5, 2)
+#(7, 6, 6, 3)
+```