chore(docs): sync doc metadata [skip ci]

Author: longsizhuo

app/docs/CommunityShare/Leetcode/2679.矩阵中的和_translated.md

@@ -1,6 +1,6 @@
 ---
 title: 2679.In the matrix and the harmony.md
-date: '2024.01.01 0:00'
+date: "2024.01.01 0:00"
 tags:
   - - Python
   - - answer
@@ -9,14 +9,16 @@ tags:
   - - Sort
   - - simulation
   - - heap（Priority queue）
-abbrlink: '5277100'
+abbrlink: "5277100"
+docId: clx9mmqqvxipdfamqciuo146
 ---
 
 # topic：
 
 [2679.In the matrix and the harmony.md](https://leetcode.cn/problems/sum-in-a-matrix/)
 
 # Thought：
+
 **One -line**
 First of all, the meaning is to find the largest number of each sub -list，Thenpopgo out，Finally ask for peace。
 The effect of traversing again and again is too bad，So I thought of using itzip一次性Traversal多个子Array。
@@ -31,6 +33,7 @@ Find the maximum：
 `[3,5,7]`
 Context：
 `15`
+
 # Code：
 
 ```python
@@ -39,8 +42,10 @@ class Solution:
         return sum(max(i) for i in \
         zip(*(sorted(sublist) for sublist in nums)))
 ```
-### *The role and the rolezip()explain
-```python 
+
+### \*The role and the rolezip()explain
+
+```python
 nums = [[1,2,7],[2,4,6],[3,5,6],[1,2,3]]
 
 for i in range(len(nums[1])):
@@ -52,28 +57,34 @@ num2 = [2,4,6]
 num3 = [3,5,6]
 num4 = [1,2,3]
 ```
+
 `zip()`The function corresponds to one -to -one elements in multiple lists，Then return onezipObject，Can uselist()Function convert to list。
+
 ```python
 for i in zip(num1, num2, num3, num4):
     print(i)
 #(1, 2, 3, 1)
 #(2, 4, 5, 2)
 #(7, 6, 6, 3)
 ```
+
 `*nums`The role ispythonNot a pointer，InsteadnumsEach element in the parameter is passed into the function。I understand here as a list。
+
 ```python
 
 # Enumerate
 print(*nums)
 # [1, 2, 7] [2, 4, 6] [3, 5, 6] [1, 2, 3]
 ```
+
 `zip(*nums)`WillnumsEach element is passed in as a parameterzip()In the function，Then return onezipObject，Can uselist()Function convert to list。
 `zip(*nums)`Equivalent to`zip(num1, num2, num3, num4)`，innum1, num2, num3, num4yesnumsElement。
+
 ```python
 for i in zip(*nums):
     print(i)
 # Equivalent
 #(1, 2, 3, 1)
 #(2, 4, 5, 2)
 #(7, 6, 6, 3)
-```
+```

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