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_307_RangeSumQueryMutable.java
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package leetcode_1To300;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _307_RangeSumQueryMutable {
/**
* 307. Range Sum Query - Mutable
*/
int[] nums;
int[] tree;
int n;
// time : O(n * logn)
public _307_RangeSumQueryMutable(int[] nums) {
n = nums.length;
tree = new int[n + 1];
this.nums = new int[n];
for (int i = 0; i < n; i++) {
update(i, nums[i]);
}
}
// time : O(logn)
public void update(int i, int val) {
if (n == 0) return;
int diff = val - nums[i];
nums[i] = val;
for (int j = i + 1; j <= n; j += j & (-j)) {
tree[j] += diff;
}
}
// time : O(logn)
public int sumRange(int i, int j) {
return sum(j + 1) - sum(i);
}
private int sum(int k) {
int sum = 0;
for (int i = k; i > 0; i -= i & (-i)) {
sum += tree[i];
}
return sum;
}
/**
* 解法2
*/
//private int[] tree;
//private int[] nums;
public void NumArray(int[] nums) {
this.nums = nums;
int sum;
int lowbit;
tree = new int[nums.length + 1];
for (int i = 1; i < tree.length; i++) {
sum = 0;
lowbit = i & (-i);
for (int j = i; j > i - lowbit; j--) {
sum = sum + nums[j - 1];
}
tree[i] = sum;
}
}
public void update2(int i, int val) {
int diff = val - nums[i];
nums[i] = val;
i++;
for (; i < tree.length; i += (i & (-i))) {
tree[i] += diff;
}
}
public int sumRange2(int i, int j) {
return sum2(j + 1) - sum2(i);
}
private int sum2(int k) {
int sum = 0;
for (int i = k; i > 0; i -= i & (-i)) {
sum += tree[i];
}
return sum;
}
}