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_356_LineReflection.java
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package leetcode_1To300;
import java.util.HashSet;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _356_LineReflection {
/**
* 356. Line Reflection
* Given n points on a 2D plane, find if there is such a line parallel to y-axis that reflect the given points.
Example 1:
Given points = [[1,1],[-1,1]], return true.
Example 2:
Given points = [[1,1],[-1,-1]], return false.
x1 + x2 = c
min max
x1 = c - x2
平行于y轴 : x : 对称 (两个点)
y : 相同
HashSet
1, 找出关于哪个轴对称
2, check
"1,1" "-1,1"
x2 = sum - pair
time : O(n)
space : O(n)
* @param points
* @return
*/
public boolean isReflected(int[][] points) {
HashSet<String> set = new HashSet<>();
int min = Integer.MAX_VALUE;
int max = Integer.MIN_VALUE;
for (int[] pair : points) {
set.add(pair[0] + "," + pair[1]);
min = Math.min(min, pair[0]);
max = Math.max(max, pair[0]);
}
int sum = min + max;
for (int[] pair : points) {
if (!set.contains(sum - pair[0] + "," + pair[1])) {
return false;
}
}
return true;
}
}