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_392_IsSubsequence.java
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package leetcode_1To300;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _392_IsSubsequence {
/**
* 392. Is Subsequence
* Example 1:
s = "abc", t = "ahbgdc"
Return true.
Example 2:
s = "axc", t = "ahbgdc"
Return false.
time : O(n);
space : O(1);
* @param s
* @param t
* @return
*/
public boolean isSubsequence(String s, String t) {
if (s == null || s.length() == 0) return true;
int i = 0;
int j = 0;
while (i < s.length() && j < t.length()) {
if (s.charAt(i) == t.charAt(j)) i++;
j++;
}
return i == s.length();
}
}