[LeetCode Sync] Runtime - 3 ms (51.44%), Memory - 18 MB (25.11%)

Author: NinePiece2

Solutions/0389-find-the-difference/README.md

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+<p>You are given two strings <code>s</code> and <code>t</code>.</p>
+
+<p>String <code>t</code> is generated by random shuffling string <code>s</code> and then add one more letter at a random position.</p>
+
+<p>Return the letter that was added to <code>t</code>.</p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<pre>
+<strong>Input:</strong> s = &quot;abcd&quot;, t = &quot;abcde&quot;
+<strong>Output:</strong> &quot;e&quot;
+<strong>Explanation:</strong> &#39;e&#39; is the letter that was added.
+</pre>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<pre>
+<strong>Input:</strong> s = &quot;&quot;, t = &quot;y&quot;
+<strong>Output:</strong> &quot;y&quot;
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>0 &lt;= s.length &lt;= 1000</code></li>
+	<li><code>t.length == s.length + 1</code></li>
+	<li><code>s</code> and <code>t</code> consist of lowercase English letters.</li>
+</ul>

Solutions/0389-find-the-difference/solution.py

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+class Solution:
+    def findTheDifference(self, s: str, t: str) -> str:
+        count = Counter(s)
+        for char in t:
+            count[char] -= 1
+            if count[char] < 0:
+                return char
+