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052.py
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36 lines (27 loc) · 936 Bytes
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"""
Problem 52
==========
It can be seen that the number, 125874, and its double, 251748, contain
exactly the same digits, but in a different order.
Find the smallest positive integer, x, such that 2x, 3x, 4x, 5x, and 6x,
contain the same digits.
Answer: a420384997c8a1a93d5a84046117c2aa
"""
from common import check
from itertools import count
PROBLEM_NUMBER = 52
ANSWER_HASH = "a420384997c8a1a93d5a84046117c2aa"
def check_factor(number, factor):
factored_number = number * factor
factored_number_set = set(str(factored_number))
number_set = set(str(number))
return number_set == factored_number_set
def check_number(number):
for factor in range(2, 7):
if not check_factor(number, factor):
return False
return True
for number in count(1):
if check_number(number):
check(number, PROBLEM_NUMBER, ANSWER_HASH)
exit()