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longest_directed_path.cpp
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109 lines (91 loc) · 2.38 KB
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// PUSH YOUR LIMITS.!!
#include<bits/stdc++.h>
using namespace std;
typedef long double ld;
#define int long long
#define RAGE ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
#define rep(i,n) for(i=0; i <n; i++)
#define repv(i,k,n) for(int i=k; i<=n; i++)
#define pb push_back
#define mp make_pair
#define F first
#define S second
#define sz(x) (int)x.size()
#define all(v) v.begin(),v.end()
#define endl '\n'
#define deb(x) cout<<#x<<" = "<<x<<endl
#define gcd __gcd
#define inf LLONG_MAX
#define minf LLONG_MIN
const int mod = (int)(1e9+7);
int power(int x,int n)
{ if(n==0) return 1;
if(n==1) return x%mod;
if(n%2==0) { int y = power(x,n/2)%mod;return (y*y)%mod;}
if(n&1) { int y = power(x,n-1);return (x%mod * y%mod)%mod;}
return 0;
}
int dx[] = {-1, 0, 1, 0, -1, -1, 1, 1};
int dy[] = { 0, 1, 0, -1, -1, 1, 1, -1};
const int maxn = 200005;
#define eps 1e-9
// ------------------------------------------------------------------
/*
longest directed path is the number of edges from one node to any
other node in a DIRECTED ACYCLIC GRAPH (DAG).
It can be calulated with help of Dp and DFS.
Initially all is zero.
dp[node] = max(dp[node] , 1+max(dp[all(child)]));
problem:
https://www.hackerearth.com/practice/algorithms/graphs/topological-sort/practice-problems/algorithm/social-graph-1-ac58bbdf/
*/
int n,m;
vector<int> vis(maxn ,0);
vector<int> adj[maxn];
vector<int> order , dp(maxn);
void dfs(int n)
{
vis[n] =1;
for(int x:adj[n])
if(!vis[x])
dfs(x);
order.pb(n);
}
void solve()
{
int i,j,k,r;
cin>>n>>m;
rep(i,m)
{
int a,b;
cin>>a>>b;
adj[a].pb(b);
}
repv(i,1,n)
if(!vis[i])dfs(i);
for(int u:order)
{
dp[u] = 1;
for(int x:adj[u])
{
dp[u] = max(dp[u] , dp[x]+1);
}
}
cout<<*max_element(dp.begin()+1,dp.end());
}
signed main()
{
RAGE;
#ifndef ONLINE_JUDGE
freopen("input.txt", "r", stdin);
freopen("output.txt", "w", stdout);
#endif
int t=1;
// cin>>t;
while(t--)
solve();
#ifndef ONLINE_JUDGE
cout<<"\nTime Elapsed: " << 1.0*clock() / CLOCKS_PER_SEC << " sec\n";
#endif
return 0;
}