@@ -298,7 +298,96 @@ milestone 3.
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301- ### 4.1 Contextualizing consensus components
301+ ### 4.1 Probability of selection
302+
303+ In the previous section we speculated as to the total cost for an attacker to
304+ secure all of the nodes necessary to publish erroneous data. In this section we
305+ will investigate the probability of those corrupted nodes being selected to
306+ reach consensus over a given statement.
307+
308+ The first example was of a proposer which has their statement verified by a
309+ subset of 10 nodes. The probability of having a specific combination of nodes
310+ (i.e. the 10 corrupted nodes) selected can be determined using the following
311+ formula:
312+
313+ $
314+ P = \frac{1}{{\binom{n}{r}}}
315+ $
316+
317+ Where $\binom{n}{r}$, pronounced "n choose r," is the number of ways to choose
318+ $r$ from $n$. In the specific use case of Orcfax, $r$ represents the number of
319+ ways to choose 10 individuals from the 100 total nodes ($n$) without regard to
320+ order.
321+
322+ - $n = 100$
323+ - $r = 10$
324+
325+ This can be represented as:
326+
327+ $
328+ \binom{100}{10} = \frac{100!}{10!(100 - 10)!} = \frac{100!}{10! \cdot 90!}
329+ $
330+
331+ ::: info [ Explanation]
332+
333+ 1 . $100!$: The factorial of 100, representing all possible arrangements of 100
334+ nodes.
335+ 2 . $10!$: The factorial of 10, representing the arrangements of the selected 10
336+ nodes.
337+ 3 . $90!$: The factorial of 90, representing the remainder of arrangements after
338+ the removal of permutations.
339+
340+ :::
341+
342+ Thus, the probability $P$ is:
343+
344+ $
345+ P = \frac{1}{\frac{100!}{10! \cdot 90!}}
346+ $
347+
348+ This gives the probability of a specific set of 10 nodes being selected from a
349+ total of 100 nodes, which is
350+
351+ $
352+ 5.78 \times 10^{-14} = 0.0000000000000578
353+ $
354+
355+ In the second example where a subset of nodes is selected, each proposes a
356+ statement, and the median is selected, the bad actor needs 11 of their corrupted
357+ nodes to participate in consensus in order to ensure that 10 of their nodes will
358+ make the 11th the median.
359+
360+ The probability of their 11 nodes being selected within a subset of 21 nodes can
361+ be expressed in the following equation:
362+
363+ $
364+ P = \frac{\binom{11}{11} \cdot \binom{89}{10}}{\binom{100}{21}}
365+ $
366+
367+ ::: info [ Explanation]
368+
369+ 1 . $\binom{11}{11}$: The number of ways to choose all 11 of the corrupted nodes
370+ (this is 1, as there's only one way to choose all 11 of them).
371+ 2 . $\binom{89}{10}$: The number of ways to choose the remaining 10 nodes from
372+ the remaining 89.
373+ 3 . $\binom{100}{21}$: The total number of ways to choose 21 nodes out of the
374+ total 100.
375+
376+ :::
377+
378+ Thus, the probability of all 11 corrupted nodes being selected within a subset
379+ of 21 nodes is approximately:
380+
381+ $
382+ 2.4904 \times 10^{-9} = 0.00000000249
383+ $
384+
385+ This section is for purposes of illustration only. Specific design choices to be
386+ made in milestone 3 can have significant impacts on how randomness is
387+ implemented and thereby the probable chance of a bad actor being able to
388+ influence consensus.
389+
390+ ### 4.2 Contextualizing consensus components
302391
303392The following demonstrates the various components of a fully decentralized node
304393within the EchoNet network; "Validator Node-1" shows each of its components
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