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MOZPWS.cpp
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105 lines (88 loc) · 2.17 KB
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#include <bits/stdc++.h>
using namespace std;
struct node{
int st, en;
long long maxVal;
node()
{
maxVal = LLONG_MIN;
st = INT_MAX;
en = -1;
}
};
int nearestPow2(int n)
{
for(int i = 1; i <= 1000000; i*=2)
{
if(n <= i)
return i;
}
}
long long findMax(vector<node> &segTree, int nodeIndex, int st, int en)
{
node n = segTree[nodeIndex];
if(n.st == st && n.en == en)
{
return n.maxVal;
}
int l = 2*nodeIndex + 1;
int r = 2*nodeIndex + 2;
if(segTree[l].st <= st && segTree[l].en >= en)
return findMax(segTree, l, st, en);
if(segTree[r].st <= st && segTree[r].en >= en)
return findMax(segTree, r, st, en);
return max(findMax(segTree, l, st, segTree[l].en), findMax(segTree, r, segTree[r].st, en));
}
int main()
{
int t,n,k,q,x,y;
cin>>t;
for(int _it = 1; _it <= t; ++_it)
{
cout<<"Case :"<<_it<<endl;
cin>>n>>k;
vector<long long> a(n);
for(int i = 0; i < n; ++i)
{
cin>>a[i];
}
int treeSize = nearestPow2(n-k+1);
vector<node> seg(2*treeSize - 1);
set<long long> mi;
for(int i = 0; i < k; ++i)
{
mi.insert(a[i]);
}
for(int i = 0; i <= (n-k); ++i)
{
seg[treeSize+i-1].maxVal= *mi.begin();
seg[treeSize+i-1].st = i;
seg[treeSize+i-1].en = i;
mi.erase(a[i]);
mi.insert(a[i+k]);
}
for(int i = 2*treeSize-2; i > 0; i-=2)
{
seg[(i-1)/2].maxVal = max(seg[i].maxVal, seg[i-1].maxVal);
seg[(i-1)/2].st = min(seg[i].st, seg[i-1].st);
seg[(i-1)/2].en = max(seg[i].en, seg[i-1].en);
}
cin>>q;
/*
for(int i = 0; i < 2*treeSize -1; ++i)
{
cout<<seg[i].maxVal<<" "<<seg[i].st<<" "<<seg[i].en<<endl;
}*/
while(q--)
{
cin>>x>>y;
x--;
y--;
y = y - k + 1;
if(y>=x)
cout<<findMax(seg, 0, x, y)<<endl;
else
cout<<"Impossible\n";
}
}
}