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Remove_K_Digits.py
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40 lines (32 loc) · 1.11 KB
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"""
Given a non-negative integer num represented as a string, remove k digits from the number so that the new number is the smallest possible.
Note:
The length of num is less than 10002 and will be ≥ k.
The given num does not contain any leading zero.
Example 1:
Input: num = "1432219", k = 3
Output: "1219"
Explanation: Remove the three digits 4, 3, and 2 to form the new number 1219 which is the smallest.
Example 2:
Input: num = "10200", k = 1
Output: "200"
Explanation: Remove the leading 1 and the number is 200. Note that the output must not contain leading zeroes.
Example 3:
Input: num = "10", k = 2
Output: "0"
Explanation: Remove all the digits from the number and it is left with nothing which is 0.
"""
class Solution:
def removeKdigits(self, num: str, k: int) -> str:
n = len(num)
if n == k: return "0"
res = []
for i in range(n):
while k and res and res[-1] > num[i]:
res.pop()
k -= 1
res.append(num[i])
while k:
res.pop()
k -= 1
return "".join(res).lstrip('0') or "0"