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Description
Hi,
i just started using htmleasy, i have been trying to configure htmleasy as
servlet impl in google appengine , but no luck, after configuring and
registering class , when i try to access a jsp page it shows , resources not
avaiable.
Is Filter is essentials (there is not documentation stat that it is required),
following is config:
<servlet>
<servlet-name>resteasy-servlet</servlet-name>
<servlet-class>
com.googlecode.htmleasy.HtmleasyServletDispatcher
</servlet-class>
<init-param>
<param-name>javax.ws.rs.Application</param-name>
<param-value>com.test.resteasygae.config.AppConfig</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>resteasy-servlet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<jsp-property-group>
<description>Common config for all the JSP</description>
<url-pattern>/*</url-pattern>
<el-ignored>false</el-ignored>
</jsp-property-group>
and my app config :
public class AppConfig extends Application {
@Override
public Set<Class<?>> getClasses() {
Set<Class<?>> services = new HashSet<Class<?>>();
services.add(MainController.class);
services.addAll(HtmleasyProviders.getClasses());
return services;
}
}
controller path
@Path("/")
@GET
public View hanldeRequest() {
return new View("index.jsp");
}
and the result :
could not find resource at path http://localhost:8888/index.jsp
when i use it with filters instead of servlets , it working fine, so i just
wanted to know , wether filter is must ?
can u help ?
What version of the product are you using?
0.7
Original issue reported on code.google.com by ramesh.l...@a-cti.com on 15 Jul 2013 at 2:28
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