-
Notifications
You must be signed in to change notification settings - Fork 51
Spruce- Rebecca Z #22
New issue
Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.
By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.
Already on GitHub? Sign in to your account
base: master
Are you sure you want to change the base?
Changes from all commits
File filter
Filter by extension
Conversations
Jump to
Diff view
Diff view
There are no files selected for viewing
| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -1,8 +1,18 @@ | ||
| from heaps.min_heap import MinHeap | ||
|
|
||
|
|
||
| def heap_sort(list): | ||
| """ This method uses a heap to sort an array. | ||
| Time Complexity: ? | ||
| Space Complexity: ? | ||
| Time Complexity: On | ||
| Space Complexity: On | ||
| """ | ||
| pass | ||
| result = [] | ||
| heap = MinHeap() | ||
|
|
||
| for item in list: | ||
| heap.add(item) | ||
|
|
||
| while len(heap.store) > 0: | ||
| result.append(heap.remove()) | ||
|
|
||
| return result | ||
| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -1,5 +1,5 @@ | ||
| class HeapNode: | ||
|
|
||
| def __init__(self, key, value): | ||
| self.key = key | ||
| self.value = value | ||
|
|
@@ -10,67 +10,105 @@ def __str__(self): | |
| def __repr__(self): | ||
| return str(self.value) | ||
|
|
||
|
|
||
| class MinHeap: | ||
|
|
||
| def __init__(self): | ||
| self.store = [] | ||
|
|
||
|
|
||
| def add(self, key, value = None): | ||
| def add(self, key, value=None): | ||
| """ This method adds a HeapNode instance to the heap | ||
| If value == None the new node's value should be set to key | ||
| Time Complexity: ? | ||
| Space Complexity: ? | ||
| Time Complexity: Ologn | ||
| Space Complexity: On | ||
|
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. ✨ The space complexity here is determined by the recursive call stack of |
||
| """ | ||
| pass | ||
| if value is None: | ||
| value = key | ||
|
|
||
| node = HeapNode(key, value) | ||
|
|
||
| self.store.append(node) | ||
| index = len(self.store) - 1 | ||
|
|
||
| self.heap_up(index) | ||
|
|
||
| def remove(self): | ||
| """ This method removes and returns an element from the heap | ||
| maintaining the heap structure | ||
| Time Complexity: ? | ||
| Space Complexity: ? | ||
| Time Complexity: Ologn | ||
| Space Complexity: O1 | ||
|
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. ✨ Because of the recursive call stack of |
||
| """ | ||
| pass | ||
| if self.empty(): | ||
| return None | ||
|
|
||
| self.swap(0, len(self.store)-1) | ||
| result = self.store.pop() | ||
| self.heap_down(0) | ||
|
|
||
| return result.value | ||
|
|
||
|
|
||
| def __str__(self): | ||
| """ This method lets you print the heap, when you're testing your app. | ||
| """ | ||
| if len(self.store) == 0: | ||
| return "[]" | ||
| return f"[{', '.join([str(element) for element in self.store])}]" | ||
|
|
||
|
|
||
| def empty(self): | ||
| """ This method returns true if the heap is empty | ||
| Time complexity: ? | ||
| Space complexity: ? | ||
| Time complexity: O1 | ||
| Space complexity: 01 | ||
|
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. ✨ |
||
| """ | ||
| pass | ||
|
|
||
| return len(self.store) == 0 | ||
|
|
||
| def heap_up(self, index): | ||
| """ This helper method takes an index and | ||
| moves the corresponding element up the heap, if | ||
| it is less than it's parent node until the Heap | ||
| property is reestablished. | ||
|
|
||
| This could be **very** helpful for the add method. | ||
| Time complexity: ? | ||
| Space complexity: ? | ||
| Time complexity: Ologn | ||
| Space complexity: O1 | ||
|
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. ✨ Because of the recursive call stack, space complexity is O(log n) |
||
| """ | ||
| pass | ||
| if index == 0: | ||
| return None | ||
|
|
||
| # left = index * 2 + | ||
| parent = (index - 1) // 2 | ||
|
|
||
| if self.store[index].key < self.store[parent].key: | ||
| self.swap(index, parent) | ||
| self.heap_up(parent) | ||
|
|
||
| def heap_down(self, index): | ||
| """ This helper method takes an index and | ||
| moves the corresponding element down the heap if it's | ||
| larger than either of its children and continues until | ||
| the heap property is reestablished. | ||
| Time Complexity: Ologn | ||
| Space Complexity: O1 | ||
|
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. ✨ Space complexity is O(log n) here because of the recursive call stack |
||
| [2, 5, 3, 6 ] | ||
| 0 1 2 3 | ||
| """ | ||
| pass | ||
| left = index * 2 + 1 | ||
| right = index * 2 + 2 | ||
|
|
||
| if left < len(self.store): # check if left node is valid | ||
| if right < len(self.store): # determine if left or right is smaller | ||
| if self.store[left].key < self.store[right].key: | ||
| smaller_child = left | ||
| self.swap(index, smaller_child) | ||
| self.heap_down(smaller_child) | ||
| else: | ||
| smaller_child = right | ||
| self.swap(index, smaller_child) | ||
| self.heap_down(smaller_child) | ||
| elif self.store[index].key > self.store[left].key: | ||
| smaller_child = left | ||
| self.swap(index, smaller_child) | ||
| self.heap_down(smaller_child) | ||
|
|
||
|
|
||
| def swap(self, index_1, index_2): | ||
| """ Swaps two elements in self.store | ||
| at index_1 and index_2 | ||
|
|
||
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
✨ Time complexity here will be O(n log n) where n is length of
list. For each of n items inlist, you performheap.add()/heap.remove()which are both log n operations.