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Cedar - Maria O.#78

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mobregong wants to merge 2 commits intoAda-C16:masterfrom
mobregong:master
Open

Cedar - Maria O.#78
mobregong wants to merge 2 commits intoAda-C16:masterfrom
mobregong:master

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@kyra-patton kyra-patton left a comment

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✨ Nice work, Maria. I left some style suggestions, but it looks like you have a good grasp on linked lists. Let me know what questions you have.

🟢

# Space Complexity: ?
# Time Complexity: O(1)
# Space Complexity: O(1)
def get_first(self):
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# Space Complexity: ?
# Time Complexity: O(1)
# Space Complexity: O(1)
def add_first(self, value):
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# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(1)
def search(self, value):
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Comment on lines +64 to +69
if current_node.next:
current_node = current_node.next
else:
return length
else:
return length
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🤓 Style suggestion to condense your code. Since your while condition is essentially to check if current_node is a Node object or None, just set current_node to current_node.next regardless of whether next is a Node or None.

If it's None, your while loop will finish executing and you can just return whatever length is at that point!

Suggested change
if current_node.next:
current_node = current_node.next
else:
return length
else:
return length
current_node = current_node.next
return length

# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(1)
def get_at_index(self, index):
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# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(1)
def add_last(self, value):
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# returns the data value and not the node
# Time Complexity: O(n)
# Space Complexity: O(1)
def find_max(self):
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# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(1)
def reverse(self):
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# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(n)
def visit(self):
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Comment on lines +147 to +149
if current_node.value == value:
self.head = current_node.next
break
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🤓I would suggest using return over break statements

Suggested change
if current_node.value == value:
self.head = current_node.next
break
if current_node.value == value:
self.head = current_node.next
return

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2 participants