[20250218] BOJ / 골드3 / 기숙사 재배정 / 김수연 #144
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🧷 문제 링크
https://www.acmicpc.net/problem/10978
🧭 풀이 시간
30분
👀 체감 난이도
✏️ 문제 설명
N명의 학생이 이전에 사용하던 기숙사와 같은 기숙사를 배정 받지 않도록 하는 경우의 수 구하기
🔍 풀이 방법
수학공식 활용해서 dp로 풀었다.
⏳ 회고
dp[i] = (dp[i-1] + dp[i-2]) * (i-1)
이게 짧은 점화식이라는데 이거 어케 생각해.................. 외워야겠다...............