[20251125] BOJ / G3 / 색상환 / 설진영 #1512
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🧷 문제 링크
https://www.acmicpc.net/problem/2482
🧭 풀이 시간
1시간
👀 체감 난이도
✏️ 문제 설명
N개의 색이 원형으로 배열된 색상환에서 인접하지 않은 K개의 색을 선택하는 경우의 수를 구하는 문제
🔍 풀이 방법
dp[i][j] = i개 중 인접하지 않게 j개 선택
dp[i][j] = dp[i-1][j] + dp[i-2][j-1]
i번째 안 선택 + i번째 선택(i-1은 불가)
⏳ 회고
원형 배열을 두 케이스로 분리해야함
왤케어렵지