[20250922] PGM / LV3 / 거스름돈 / 김수연 #954
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🧷 문제 링크
https://school.programmers.co.kr/learn/courses/30/lessons/12907
🧭 풀이 시간
40분
👀 체감 난이도
✏️ 문제 설명
돈의 종류 money가 주어질 때, n원을 만들 수 있는 방법 수 구하기
🔍 풀이 방법
dp사용
점화식 : dp[i][j] = (dp[i - 1][j] + dp[i][j - money[i - 1]])
지금까지 나온 돈의 종류로 현재 금액 j 만드는 경우 +
새로운 돈의 종류로 현재 금액 j 만드는 경우
⏳ 회고
dp.......어렵다