FireURL (v.0.3.1)

Open url from a POST request. Simple Python script that fires a URL from a POST request to the server computer.

Requirements

• Python 2.x
• Computer running Linux, Windows, Mac with any browsers

How to use

Start fireURL with one of the followings:

python fireURL.py # Will start fireURL on default port 8000

or

python fireURL.py 6073  # Will start fireURL on port 6073.

Via POST request

Send a POST request to the running server. Using curl in this example.

curl --data "url=https://google.com" 192.168.1.x.x:8000

If you are not using curl, make sure you format the data-form as followings:

{
  "url": "https://google.com"
}

Via GET request

Starting from version 0.3, GET requests will also be supported. Usage as following:

URL format:

GET http://SERVER_ADDR:PORT/?url=URL_TO_BE_FIRED

Example using curl:

curl http://192.168.x.x/?url=http://facebook.com

Format of url

The protocol of the URL can be omitted, fireURL will automatically prepend http:// in front. For example:

{
  "url": "google.com"
}

will automatically be interpreted as url="http://google.com".

Server computer will now show up a new browser window. Enjoy!