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Original file line number Diff line number Diff line change
@@ -0,0 +1,24 @@
from typing import List, Union, Collection, Mapping, Optional
from abc import ABC, abstractmethod

class Solution:
def twoSum(self, nums: List[int], target: int) -> List[int]:

answer = dict()

for k, v in enumerate(nums):

if v in answer:
return [answer[v], k]
else:
answer[target - v] = k

return []








Original file line number Diff line number Diff line change
@@ -0,0 +1,22 @@
from typing import List, Union, Collection, Mapping, Optional
from abc import ABC, abstractmethod
import re

class Solution:
def isPalindrome(self, s: str) -> bool:

# To lowercase
s = s.lower()

# Remove non-alphanumeric characters
s = re.sub(pattern=r'[^a-zA-Z0-9]', repl='', string=s)

# Determine if s is palindrome or not
len_s = len(s)

for i in range(len_s//2):

if s[i] != s[len_s - 1 - i]:
return False

return True
Original file line number Diff line number Diff line change
@@ -0,0 +1,32 @@
from typing import List, Union, Collection, Mapping, Optional
from abc import ABC, abstractmethod
from collections import deque, defaultdict

class Solution:
def canFinish(self, numCourses: int,
prerequisites: List[List[int]]) -> bool:
# Build adjacency list and in-degree array
graph = defaultdict(list)
in_degree = [0] * numCourses

for course, prereq in prerequisites:
graph[prereq].append(course)
in_degree[course] += 1

# Add all courses with no prerequisites to queue
queue = deque([i for i in range(numCourses) if in_degree[i] == 0])
courses_taken = 0

# Process courses
while queue:
course = queue.popleft()
courses_taken += 1

# Reduce in-degree for dependent courses
for next_course in graph[course]:
in_degree[next_course] -= 1
if in_degree[next_course] == 0:
queue.append(next_course)

# If we took all courses, no cycle exists
return courses_taken == numCourses
Original file line number Diff line number Diff line change
@@ -0,0 +1,44 @@
function canFinish(numCourses: number, prerequisites: number[][]): boolean {
// Build adjacency list and in-degree array
const graph: Map<number, number[]> = new Map();
const inDegree: number[] = new Array(numCourses).fill(0);

// Initialize graph
for (let i = 0; i < numCourses; i++) {
graph.set(i, []);
}

// Build graph and calculate in-degrees
for (const [course, prereq] of prerequisites) {
graph.get(prereq)!.push(course);
inDegree[course]++;
}

// Add all courses with no prerequisites to queue
const queue: number[] = [];
for (let i = 0; i < numCourses; i++) {
if (inDegree[i] === 0) {
queue.push(i);
}
}

let coursesTaken = 0;

// Process courses using BFS (Kahn's algorithm)
while (queue.length > 0) {
const course = queue.shift()!;
coursesTaken++;

// Reduce in-degree for dependent courses
for (const nextCourse of graph.get(course)!) {
inDegree[nextCourse]--;
if (inDegree[nextCourse] === 0) {
queue.push(nextCourse);
}
}
}

// If we took all courses, no cycle exists
return coursesTaken === numCourses;
}

Original file line number Diff line number Diff line change
@@ -0,0 +1,41 @@
import unittest
from src.my_project.interviews.top_150_questions_round_22\
.ex_88_course_schedule import Solution
from typing import Optional, List


class CourseScheduleTestCase(unittest.TestCase):

def test_example_1(self):
"""
Example 1:
Input: numCourses = 2, prerequisites = [[1,0]]
Output: true
Explanation: There are a total of 2 courses to take.
To take course 1 you should have finished course 0. So it is possible.
"""
solution = Solution()
numCourses = 2
prerequisites = [[1, 0]]
expected = True

result = solution.canFinish(numCourses, prerequisites)
self.assertEqual(result, expected)

def test_example_2(self):
"""
Example 2:
Input: numCourses = 2, prerequisites = [[1,0],[0,1]]
Output: false
Explanation: There are a total of 2 courses to take.
To take course 1 you should have finished course 0, and to take course 0
you should also have finished course 1. So it is impossible.
"""
solution = Solution()
numCourses = 2
prerequisites = [[1, 0], [0, 1]]
expected = False

result = solution.canFinish(numCourses, prerequisites)
self.assertEqual(result, expected)