This is a fork of a great library when-switch which seems no longer maintained.
Now I stopped maintaining this fork too. If you would like to have a similar behaviour built in JavaScript, please support the
pattern matching proposal!
This extension will never be as good as the native support.
You can use ts-when in a functional way, using a single expression:
import when from 'ts-switch'
const getDrinkPrice = drink =>
when(drink)
.is('Coke', 1.5)
.is('Pepsi', 1.8)
.else(2.0)You can return a value when given assertion is correct
const x = when
.true(someVariable === true, "some variable is true")
.else("some variable is false")You can use match method with any object exposing a test method.
const getCaseStyle = text =>
when(text)
.match(/^([A-Z][a-z]*)+$/, 'UpperCamelCase')
.match(/^([a-z]+[A-Z][a-z]*)+$/, 'LowerCamelCase')
.match(/^([a-z]+_[a-z]+)+$/, 'SnakeCase')
.else('Unknown')type SpaceObject = { x: number; y: number; z: number }
type Cube = SpaceObject & { width: number }
type Sphere = SpaceObject & { radius: number }
const SpaceObjectSchema = {
test: (_: any): _ is SpaceObject =>
typeof _.x === 'number' &&
typeof _.y === 'number' &&
typeof _.z === 'number'
}
const CubeSchema = {
test: (_: any): _ is Cube =>
typeof _.width === 'number' && SpaceObjectSchema.test(_)
}
const SphereSchema = {
test: (_: any): _ is Sphere =>
typeof _.radius === 'number' && SpaceObjectSchema.test(_)
}
const getObjectVolume = (object: SpaceObject) =>
// Each match handler will receive correct static type
when(object)
.match(CubeSchema, cube => cube.width ** 3)
.match(SphereSchema, sphere => Math.PI * 3 / 4 * sphere.radius ** 3)
.else(_ => null)
matchandiscan both be used in the samewhenexpression.
when is fully compatible with TypeScript, and will check the types you return in each is expression:
const getDrinkPrice = (drink: 'Pepsi' | 'Coke' | 'Orangina'): number =>
when(drink)
.is('Coke', 1.5)
.is('Pepsi', 1.8)
.else(2.0)Here the return type of the when expression will be number
For each is or else expression added to the current when expression, the type is added as an union to the previous type.
const getDrinkPrice = (drink: 'Pepsi' | 'Coke' | 'Orangina') =>
when(drink)
.is('Coke', 1.5)
.is('Pepsi', true)
.else('Free')Here the return type of getDrinkPrice expression will be number | string | boolean