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4 changes: 2 additions & 2 deletions docs/chapter02/3_1.md
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Original file line number Diff line number Diff line change
Expand Up @@ -358,14 +358,14 @@ $$\Sigma\_{a|b} = \Lambda_{aa}^{-1} \qquad{(2.73)}$$

- 이제 당연히 \\( {\bf x}\_a \\) 의 1차식과 관련된 텀들을 모아 이 계수를 확인해야 한다. (평균을 구하기 위해)

$${\bf x}_a^T\{\Lambda_{aa}{\pmb \mu}_a - \Lambda({\bf x}_b-{\pmb \mu}_b)\} \qquad{(2.74)}$$
$${\bf x}_a^T\{\Lambda_{aa}{\pmb \mu}_a - \Lambda_{ab}({\bf x}_b-{\pmb \mu}_b)\} \qquad{(2.74)}$$

- \\( \Lambda\_{ba}^T=\Lambda\_{ab} \\) 임을 이미 알고 있다.

- 위의 식은 결국 \\( \Sigma\_{a\|b}^{-1} \; {\pmb \mu}\_{a\|b} \\) 와 같아져야 한다.
- 식을 전개하면 다음과 같게 된다.

$$\Sigma_{a|b}^{-1}\; {\pmb \mu}_{a|b} = \{\Lambda_{aa}{\pmb \mu}_a - \Lambda({\bf x}_b-{\pmb \mu}_b)\}$$
$$\Sigma_{a|b}^{-1}\; {\pmb \mu}_{a|b} = \{\Lambda_{aa}{\pmb \mu}_a - \Lambda_{ab}({\bf x}_b-{\pmb \mu}_b)\}$$

$${\pmb \mu}_{a|b} = \Sigma_{a|b}\{\Lambda_{aa}{\pmb \mu}_a - \Lambda_{ab}({\bf x}_b-{\pmb \mu}_b)\}\\
= {\pmb \mu}_a - \Lambda_{aa}^{-1}\Lambda_{ab}({\bf x}_b-{\pmb \mu}_b) \qquad{(2.75)}$$
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